def ver_val(s):
 	s = s.split(".")
 	length = len(s)
 	s += ['0']*(3-length) # Outer pad array right zeros.
 	s = ['0'*(3-len(x)) + x for x in s]	# Inner pad string left zeros
 	s += [str(length)]	# Take length into consideration, less is better.
 	return ''.join(s)


def solution(l):
    d = dict()
    for version in l: d[version] = ver_val(version)
    l.sort(key=lambda x: d[x])
    return l